Monkeying with Clojure’s comp Function
A slight modification to Clojure’s comp
function gives me more power:
(defn comp+ ([] identity) ([f] f) ([f g] (fn ([] (f (g))) ([x] (f (g x))) ([x y] (f (g x y))) ([x y z] (f (g x y z))) ([x y z & args] (f (apply g x y z args))))) ([f g h] (fn ([] (f (g (h)))) ([x] (f (g (h x)))) ([x y] (f (g (h x y)))) ([x y z] (f (g (h x y z)))) ([x y z & args] (f (g (apply h x y z args)))))) ([f1 f2 f3 & fs] (let [fs (reverse (list* f1 f2 f3 fs))] (fn [& args] (loop [ret (apply (first fs) args) fs (next fs)] (if fs (recur ((first fs) ret) (next fs)) ret)))))) ;; allowing (require ‘clojure.string) (for [f (map #(apply comp+ %) [[keyword name] [] [name clojure.string/upper-case]]) e '[foo bar]] (f e)) ;=> (:foo :bar foo bar "FOO" "BAR")
I added a function body to comp+
handling the case where it’s given no function, returning the identity
function. This let’s me use comp+
in more interesting ways without requiring that I handle the case of no arguments explicitly and without exploding when I don’t.
Just one of those little things I guess.
:f
2 Comments, Comment or Ping
Alf
I’m a newbie to Clojure, but wanted to test the code. Couldn’t quite make it work though. Modified the test to the following:
(require ‘clojure.contrib.string) (for [f (map #(apply comp+ %) [[keyword name] [] [clojure.contrib.string/upper-case name]]) e ‘[foo bar]] (f e)))
The change was really just to require clojure.contrib string, and reversing the final vectors values from [name clojure.string/upper-case] to [clojure.contrib.string/upper-case name].
This seems to give the expected result.
Also wondering why you are not basing your comp+ function on the existing comp function. The following has the same result. Is this less efficient than copying the code?
(defn comp+ ([] identity) ([f & fs] (apply comp f fs)))
Aug 19th, 2010
fogus
Thanks for the call on
require
— fixed.All of my “monkeying” posts work against the original source.
Aug 19th, 2010
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